Question

find the value of a and b, if
see the photo


plsss help...with explanation..

thankyou,
snipermaster101​

Answer 1

Step-by-step explanation:

BTP,

$\frac{ \sqrt{3 } - 1 }{ \sqrt{3} + 1} = a + b \sqrt{3} \\ = > \frac{ \sqrt{3 } - 1 }{ \sqrt{3} + 1} \times \frac{ \sqrt{3 } - 1 }{ \sqrt{3} - 1} = a + b \sqrt{3} \\ = > \frac{ {( \sqrt{3} )}^{2} - 2 \sqrt{3} + {(1)}^{2} }{ {( \sqrt{3} )}^{2} - {(1)}^{2} } = a + b \sqrt{3} \\ = > \frac{3 - 2 \sqrt{3} + 1}{3 - 1} = a + b \sqrt{3} \\ = > \frac{4 - 2 \sqrt{3} }{2} = a + b \sqrt{3} \\ = > \frac{2(2 - \sqrt{3} )}{2 \times 1} = a + b \sqrt{3} \\ = > (2 - \sqrt{3} ) = a + b \sqrt{3}$

Comparing both sides , we get ,

$a = 2 \\ and</em><em>,</em><em> \: b \sqrt{3} = - \sqrt{3} \\ \: \: \: \: \: \: \: \: b = - 1$