Question

find the value of A and B if Sin(a+2b) =√3/2 and cos (a+b) = 0​

Answer 1

✍️ Sin(a+2b) = √3/2

(a+2b)= 60°-----------(1)

✍️ Now, Cos(a+b)= 0

(a+b)= 90°------------(2)

✍️ Now, Subtracting (2) from (1)

gives ,⭐b = -30°⭐

✍️ Now put the value of b in equation 2

so we get ,⭐ a = 120°⭐

I hope it helps you...