Question

Find the value of a and b if
$\frac{3 + \sqrt{2} }{3 - \sqrt{2} {} } = a + b \sqrt{2}$

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Answer 1

$\huge\color{hotpink}\boxed{\colorbox{black}{Answer}}$

$\frac{(3 + \sqrt{2} )(3 + \sqrt{2}) }{ (3 - \sqrt{2} + 3 + \sqrt{2} ) } = a + b \sqrt{2} \\ \frac{9 + 6 \sqrt{2} + 2 }{9 - 2} = a + b \sqrt{2} \\ \frac{11 + 6 \sqrt{2} }{7} = a + b \sqrt{2} \\ \frac{11}{7} + \frac{6 \sqrt{2} }{7} = a + b \sqrt{2} \\ \\ a = \frac{11}{7} and b = \frac{6}{7}$

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Answer 2

Answer:

Answer :

In attachment

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