Question

Find the value of a and b if the line5bx-3ay=30 passes through ( -1, 0) and ( 0,-3)​

Answer 1

Answer:

a=10/3, b= -6

Explanation:

Case 1:

x=-1, y=0

(5b)(-1) - 0 = 30

-5b=30

=>b= -6

Case 2:

x=0, y= -3

0- (3a)(-3)=30

9a=30

=>a=10/3

Answer 2

The required values of a and b are $a=\frac{30}{9} , b=-6$  respectively when the line $5bx-3ay=30$ passes through (-1,0) and (0,-3).

Given:

The line $5bx-3ay=30$ passes through (-1,0) and (0,-3).

To Find:

the values of a and b

Solution:

We can find the solution to this problem in the following way.

We know that when the line with an equation passes through a point, the coordinates of that point satisfy the line equation.

We shall use all the relevant data to arrive at the solution to this problem.

The point (-1,0) satisfies the given line. So we can write the following.

$5bx-3ay=30\\5b\times (-1) -3a\times 0=30\\-5b=30\\b=-6$

The point (-1,0) satisfies the given line. So we can write the following.

$5bx-3ay=30\\5b\times 0-3a\times (-3) =30\\9a=30\\a=\frac{30}{9}$

Thus the final answer is that the required values of a and b are $a=\frac{30}{9} , b=-6$  respectively when the line $5bx-3ay=30$ passes through (-1,0) and (0,-3).

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