Question

find the value of a and b,if the zeroes of the quardratic polynomial Xsquar+(a+1)x+b are 2 and -3

Answer 1

Heya !!!


(2) and (-3) are the two zeroes of the given polynomial.



P(X) = X²+(A+1)X + B


P(2) = (2)² + (A +1) × 2 + B



=> 4 + 2A + 2 + B = 0

=> 2A + B = -6 ----------(1)



And,



P(-3) = (-3)² + (A+1) × -3 + B


=> 9 -3A - 3 + B = 0


=> 3A - B = 6 ---------(2)



From equation (1) we get,

2A + B = -6


2A = -6 - B


A = -6 - B/2 ----------(3)



Putting the value of A in equation (2)


3A - B = 6


3 × (-6 - B/2) - B = 6



-18 - 3B/2 - B = 6


-18 - 3B - 2B = 12



-5B = 12 + 18


-5B = 30


B = -30/5 => -6


Putting the value of B in equation (3)



A = -6 - B/2 => -6 - 6/2


A = -12/2 => -6

Hence,



A = -6 and B = -6 .




HOPE IT WILL HELP YOU....... :-)

Answer 2

hope its helpful.....