Math, asked by Riyakaushik, 1 year ago

find the value of A and B if under root 3 + 1 upon under root 3 minus 1 is equal to a + b under root 3

Answers

Answered by shakti1234
153
PLZ MARK MY ANSWER AS BRAINLIEST
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DaIncredible: great sir ^_^
Answered by DaIncredible
124
Heya Friend,
Here is the answer you were looking for:

Identities used :

 {(a + b)}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab \\ (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

 \frac{ \sqrt{3} + 1 }{ \sqrt{3}   - 1} = a + b \sqrt{3}  \\

On rationalizing the denominator we get,

 =  \frac{ \sqrt{3} + 1 }{ \sqrt{3}  - 1}   \times  \frac{ \sqrt{3}  + 1 }{ \sqrt{3}  - 1}  \\  \\  =  \frac{ {( \sqrt{3}) }^{2}  +  {(1)}^{2}  + 2( \sqrt{3})(1) }{ {( \sqrt{3} )}^{2}  -  {(1)}^{2} }  \\  \\  =  \frac{3 +  1+ 2 \sqrt{3} }{3 - 1}  \\  \\  =  \frac{4 + 2 \sqrt{3} }{2}  \\  \\  =  \frac{2(2 +  \sqrt{3} )}{2}  \\  \\   2 +  \sqrt{3}  = a + b \sqrt{3}  \\  \\ a = 2 \:  :  \: b = 1

Hope this helps!!!

Feel free to ask in the comment section if you have any doubt regarding to my answer...

@Mahak24

Thanks...
☺☺

yuvrajadkarp8eygz: While rationalising, numerators & denominator should be same. please make correction.
Riyakaushik: dude!is this anwer is wrong
yuvrajadkarp8eygz: no
shakti1234: wrong
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