Question

Find the value of a and b , if x=0,x=-1and the roots of the polynomial f(x)=2x^3-3x^2+ax+b.

Answer 1

Answer:

$2(0) {}^{3} - 3(0) {}^{2} + a(0) + b = \\ 2( - 1) {}^{3} - 3( - 1) {}^{2} + a( - 1) + b \\ b = - 2 - 3 - a + b \\ b - b + a = - 5 \\ a = - 5 \\ now \: we \: can \: find \: the \: value \: of \: b \: easily \\ 2(0) {}^{3} - 3(0) {}^{2} - 5(0) + b = 0 \\ b = 0 \\ hope \: it \: will \\ be \: helpful \: to \: u \: follow \: me \: and \: mark \: as \: brainliest$