find the value of A and B if x square minus 4 is a factor of ax 4 + 2 x 3 - 3 x square + bx - 4 and hence is it completely
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ax^4+2x^3-3x^2+bx-4=0
x^2-4 is factor so that 2,-2 roots of above equation
if x=2
16a+16-12+2b-4=0
16a+2b=0
8a+b=0
if x=-2
16a-16-12-2b-4=0
16a-2b=32
8a-b=16
a=1,b=-8
x^2-4 is factor so that 2,-2 roots of above equation
if x=2
16a+16-12+2b-4=0
16a+2b=0
8a+b=0
if x=-2
16a-16-12-2b-4=0
16a-2b=32
8a-b=16
a=1,b=-8
gsnarayana:
hope it helps you
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