Find the value of 'a' and 'b' , if x²-1 is a factor of ax³+x² -2x+b
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0
Answer:
Step-by-step explanation:
p(x)=ax^3+x^2+-2x+b
quotient:- kuch kuch
answer kuch kuch
diy
Answered by
2
Step-by-step explanation:
x^2 -1 =0
=> x^2 = 1
=> x = 1
also x^3 =1 (1×1×1 = 1)
substituting this value in the polynomial we get:
a×(1)^3 +(1)^2 -2×1 + b =0
= a + 1 - 2 +b =0
=> a + -1 +b = 0
=> a + b = 1 ( transposing 1 to RHS)
Had the second equation being given, we would have got the values of a & b
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