Question

find the value of a and b in √3+√2/√3-√2=a+b√2​

Answer 1

Answer:

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{ 3 } + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ = \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ = 5 + 2 \sqrt{3} \sqrt{2} \\ a + b \sqrt{2} = 5 + 2 \sqrt{3} \sqrt{2} \\ a = 5 \\ b = 2 \sqrt{3}$

Answer 2

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