Question

find the value of a and b in : 3-√5/3+2√5 = a√5-b/11​

Answer 1

$3 - \frac{ \sqrt{5} }{3} + 2 \sqrt{5} = a \sqrt{5} - \frac{b}{11} \\ \\ multiplying \: throughout \: by \: 33 \\ \\ 99 - 11 \sqrt{5} + 66 \sqrt{5} = 33a \sqrt{5} - 3b \\ 55 \sqrt{5} + 99 = 33a \sqrt{5} - 3b \\ (33)( \frac{55}{33} ) (\sqrt{5} ) - 3(-33) = 33a \sqrt{5} - 3b \\ \\ on \: comparing \: lhs \: and \: rhs \\ \\ a = \frac{55}{33} \: and \: b = - 33$

Answer 2

Answer:

Step-by-step explanation:

Hope it will help you..