Question

find the value of A and B in 3 by root 3 minus root 2 is equal to a root 3 minus b root 2​

Answer 1

Answer:

10

Step-by-step explanation:

3 + 3 + 2 + 2 = 10

Answer 2

Answer:

$\bf a=3 \ and \ b=-3$

Step-by-step explanation:

$\frac{3}{\sqrt{3}-\sqrt{2} } =a\sqrt{3} -b\sqrt{2} \\\\LHS=\frac { 3 (\sqrt{3}+\sqrt{2) }} {(\sqrt{3}- \sqrt{2} )(\sqrt{3}+\sqrt{2} }\\\\=\frac { 3 (\sqrt{3}+\sqrt{2) }} {3-2}\\\\\bf=3\sqrt{3} +3\sqrt{2} =a\sqrt{3} -b\sqrt{2} \ (given)\\\\On \ comparison \ we \ get\\\\a=3 \ and \ b=-3$