Question

find the value of a and b, in a=1 and b=2; 25a^2-40ab + 16b^2​

Answer 1

Step-by-step explanation:

25a^2 = (5a)^2

-40ab=-(2*5a*4b)

16b^2=(4b)^2

hence from (a-b)^2=a^2+b^2-2ab

=(5a-4b)^2

zeroes are a=4b/2 and b =5a/4

keeping the values in the square we can extract for a=1 and b = 2