Question

find the value of 'a'and'b' in each of the following √3-1/√3+1=a+b√3​

Answer 1

Answer:

a = 2 and b = - 1.

Step-by-step explanation:

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} = a + b \sqrt{3}$

L.H.S. , Rationalizing the denominator we get:

$= \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ \\ = \frac{ {( \sqrt{3} )}^{2} + {(1)}^{2} - 2. \sqrt{3}.1 }{ {( \sqrt{3}) }^{2} - {(1)}^{2} } \\ \\ = \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \\ \\ = \frac{4 - 2 \sqrt{3} }{2} \\ \\ \bf = 2 - \sqrt{3}$

Equating L.H.S and R.H.S we get:

2 - √3 = a + b√3

a = 2 and b = - 1

Answer 2

Answer:

HOPE IT HELPS BUDDY....