find the value of A and B in each of the following
√3+1/√3-1=a+b√3
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Answered by
1
Answer:
2+√3
a=2
b=1
Step-by-step explanation:
=√3+1(√3+1)/√3-1 .......(multiply the denominator's conjugate)
=(√3+1)²/√3-1
=(3+2√3+1)/2
=2+√3
Hope it helps.........
@Khushirout
Answered by
2
√3+1/√3-1=a+b√3
√3+1/√3-1*√3+1/√3+1=a+b√3
(√3+1)^2/3-1=a+b√3
3+1+2√3/2=a+b√3
4+2√3/2=a+b√3
2+√3=a+b√3
so a=2 & b=1
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