Math, asked by artihari8936, 7 months ago

find the value of A and B in each of the following
√3+1/√3-1=a+b√3

Answers

Answered by khushirout22
1

Answer:

2+√3

a=2

b=1

Step-by-step explanation:

=√3+1(√3+1)/√3-1 .......(multiply the denominator's conjugate)

=(√3+1)²/√3-1

=(3+2√3+1)/2

=2+√3

Hope it helps.........

@Khushirout

Answered by gunjansingh963
2

√3+1/√3-1=a+b√3

√3+1/√3-1*√3+1/√3+1=a+b√3

(√3+1)^2/3-1=a+b√3

3+1+2√3/2=a+b√3

4+2√3/2=a+b√3

2+√3=a+b√3

so a=2 & b=1

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