Find the value of 'a' and 'b'
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(5+√3)/(√5-√3) = a/2 + 3b√15
Rationalising the LHS
(5+√3)(√5+√3) / (√5-√3)(√5+√3) = a/2 + 3b√15
5(√5+√3) + √3(√5+√3) / (√5)²-(√3)² = a/2 + 3b√15
5√5+5√3 + √15+3/ 5-3 = a/2 + 3b√15
5√5+5√3+3 + √15/ 2 = a/2 + 3b√15
(5√5+5√3+3)/2 + √15/ 2 = a/2 + 3b√15
a = 5√5+5√3+3
3b = 1/2
b = 1/6
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