Question

find the value of a and b
please answer it correctly​

Answer 1

Step-by-step explanation:

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } + \frac{3 - \sqrt{7} }{3 + \sqrt{7} } \\ = \frac{(3 + \sqrt{7} )(3 + \sqrt{7}) + (3 - \sqrt{7} )(3 - \sqrt{7} )}{(3 - \sqrt{7} )(3 + \sqrt{7} )} \\ = \frac{ {(3 + \sqrt{7}) }^{2} + {(3 - \sqrt{7}) }^{2} }{ ({3})^{2} - {( \sqrt{7} )}^{2} } \\ = \frac{ 9 + 6 \sqrt{7} + 7 + 3 - 6 \sqrt{7} + 7 }{9 - 7} \\ = \frac{26}{2} = 13$

a = 13, b = 0

Answer 2

Step-by-step explanation:

$\begin{gathered} \frac{3 + \sqrt{7} }{3 - \sqrt{7} } + \frac{3 - \sqrt{7} }{3 + \sqrt{7} } \\ = \frac{(3 + \sqrt{7} )(3 + \sqrt{7}) + (3 - \sqrt{7} )(3 - \sqrt{7} )}{(3 - \sqrt{7} )(3 + \sqrt{7} )} \\ = \frac{ {(3 + \sqrt{7}) }^{2} + {(3 - \sqrt{7}) }^{2} }{ ({3})^{2} - {( \sqrt{7} )}^{2} } \\ = \frac{ 9 + 6 \sqrt{7} + 7 + 3 - 6 \sqrt{7} + 7 }{9 - 7} \\ = \frac{26}{2} = 13\end{gathered}</p><p>a = 13, b = 0$