find the value of A and B so that 2 x cube + x square + X + b has X + 2 and 2x - 1 as factors
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Polynomial , x -ax -13x + b has two factors (x-1) and (x +3)
it means, x = 1 and -3 are the roots (zeros ) of x° -ax2 -13x + b.
so,
put x = 1 in polynomial .
(1) 3 -a (1)2 -13(1) + b = 0
1 - a -13 + b = 0
-a + b = 12 --(1)
put x = -3
(-3)* -a(-3)2 -13(-3) + b = 0
-27 -9a +39 + b = 0
-9a + b = -12 -(2)
subtract equation (1) and (2)
-a + b + 9a - b = 12 + 12
8a = 24
a= 3
put a = 3 in equation (1)
b = 15
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