find the value of a and b so that 2x4-3x3-4x2+ax+b is divisible by x2+1 ans as soon as possible please send pic
Answers
ANSWER :-
Dividing 2x⁴- 3x³- 4x²+ ax + b by x² + 1 by long division method,
x²+1 )2x⁴- 3x³- 4x²+ ax + b(2x² - 3x - 6
2x⁴ + 2x²
-3x³ - 6x² + ax
-3x³ -3x
-6x² + x(a + 3) + b
-6x² - 6
x(a + 3) + (b + 6)
since given polynomial is divisible bt x² + 1 , remainder will be zero .
so,
→ x(a + 3) + (b + 6) = 0
→ x(a + 3) + (b + 6) = x * 0 + 0
comparing,
→ a + 3 = 0
→ a = (-3) (Ans.)
and,
→ b + 6 = 0
→ b = (-6) (Ans.)
xy-7 =3 is not a linear equation is two variables since the term xy is degree is
https://brainly.in/question/39008370
Given : 2x⁴-3x³-4x²+ax+b is divisible by x²+1
To Find : Values of a and b
Solution:
divisible by x²+1
=> x² = - 1
=> x = ± i
2x⁴-3x³-4x²+ax+b
x = i
=> 2(i)⁴ - 3(i)³-4(i)²+ai+b = 0
=> 2 + 3i + 4 + ai + b = 0
=> (a + 3)i + (b + 6) = 0
Equating real and imaginary parts
=> a =-3 b = - 6
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