Find the value of a and b so that the polynomial x cube minus 3 x square + a x + b is exactly divisible by x minus 21
Answers
Answered by
0
Answer:
x^3 - 3x^2+ax +b
x-21=0
x=21
21^3-3(21)^2+21a+b=0
9261-1323+21a+b=0
7938+21a+b=0
21a+b=-7938
a+b= 7938/21
a+b=378
Similar questions