Question

Find the value of a and b so that the polynomial
x² - ax² - 13 x+b has (x-1) and (x+3) as factors

Answer 1

Step-by-step explanation:

$given \: \: that \: (x - 1) \: and \: (x + 3) \\ \: is \: factor \: of \: the \: \\ given \: polynomial \: \: {x}^{2} - a {x}^{2} - 13x + b \\ then \: the \: value \: of \: x \: satisfy \: the \: polynomial \\ hence \\ 1 - a - 13 + b = 0 \\ a - b = - 12........(1) \\ \\ \\ and \\ \\ 9 - 9a + 39 + b = 0 \\ 9a - b = 48....(2) \\ solving \: 1 \: and \: 2 \: \: we \: get \: \\ a = 6 \: \: \: \: b = 18 \\ \\ \\ \\ hope \: it \: will \: help \: you.....$