find the value of a and b so that the polynomial (x3-1x2+ax+b) is exactly divisible by (×-1as well ad ×-
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Answer:
x 3 −10x 2 +ax+b=f(x) if f(x) is divisible by (x−1) andx−2)⇒f(1)=0=f(2) f(1)=1−10+a+b=0⇒a+b= f(2)=8−40+2a+b=0⇒2a+b=32 ∴a=23 b=−14
Answered by
1
Answer:
x
3
−10x
2
+ax+b=f(x)
if f(x) is divisible by (x−1) and (x−2)
⇒f(1)=0=f(2)
f(1)=1−10+a+b=0⇒a+b=9
f(2)=8−40+2a+b=0⇒2a+b=32
∴a=23 b=−14
Step-by-step explanation:
hope it helps you
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