Find the value of ' a ' and ' b ' so that the polynomial x³ + ax² + bx - 45 has ( x - 1 ) and ( x + 5 ) as its factors. Find the third factor .
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x- 1
x = 1
and x +5
x = - 5
x³ + ax² + bx - 45
putting x value 1
1 ³ + a(1)² + b ( 1 ) - 45
1 + a + b - 45
a + b - 44
a + b = 44
putting - 5
-5³ + a(-5)² + b (-5) - 45
-125 + a25 - b5 - 45
a25 - b5 - 170
a25 - b5. = 170
a. + b = 45
a25 - b5 = 170
- +. -
25 + b 6. = - 125
b6 = - 125 - 25
b6 = - 150
b = -150/ 6
b = -25
a + b = 45
a - 25 = 45
a = 45 - 25
a = 70
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