Find the value of a and b so that x+1 and x-1 are factors of f(x)=x⁴-ax³+2x²-3x+b
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Answer:
let try
Step-by-step explanation:
Hence the zeroes are-1and+1
p(-1)=(-1)^4-a(-1)^3+2(-1)^2-3(-1)+b
=1+a+2+3+b
i.e a+b=-6
p(1)=(1)^4-a(1)^3+2(1)^2-3(1)+b
=1-a+2-3+b
=-a+b+0
i.e-a+b=0
by solving we get a=3andb=-3
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