find the value of a and b so that x-1 and x+2 are factors of f(x)=2x³+ax²+bx-14
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Answer:
If x - 1 is a factor..
then ;
x - 1 = 0
x = 1
p(1) = 2(1)^3 + a(1)^2 + b(1) - 14
0 = 2 + a + b - 14
a + b = 12
a = 12 - b -----(1)
x + 2 is a factor ...
then ;
x + 2 = 0
x = -2
p(-2) = 2 (-2)^3 + a(-2)^2 + b(-2) - 14
0 = -16 -4a -2b - 14
4a + 2b + 14 + 16 = 0
2a + b + 7 + 3 = 0
2a + b = -10 ----(2)
substituting eq(1) in eq(2)
2 (12 - b ) + b = -10
24 - 2b + b = -10
24 - b = - 10
b = 24 + 10
b = 34 ----(3)
substituting eq (3) in eq (1)
a = 12 - b
a = 12 - 34
a = -22
hope it helps
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