find the value of a and b so that x+1 and x-2 are factors of x4+ax3+2x2-2x+b
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a= -2 b=2
Step-by-step explanation:
I think the question should be :-
p(x) = x⁴ - ax³ -3x² + 2x + b
We have to find the values of "a" and "b"
Given :-
(x+1) and (x-1) are the factors of the p(x)
Hence ,
zeroes are = -1 and 1
p(1) = 1⁴ + a×1³ - 3×1² + 2× 1 + b
= 1 + a - 3 + 2 + b = 0
= a + b = 0 --------> [1]
p(-1) = (-1)⁴ + a×-1³ - 3×-1² + 2× -1 + b
= 1 - a - 3 -2 + b
= -4 - a + b
-a + b = 4 --------> [2]
Adding equations 1 and 2 ,
2b = 4
b = 2
Put this value in p(x) :-
we get ,
a = -2
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