find the value of a and b so that x^3-10x^2+ax+b^3 is exactly divisible by x-1 as well as x-2
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Hey.
Here is the answer.
Polynomial , x³ +10x² + ax + b is exactly divisible by ( x -1) and (x -2)
it means x = 1 and 2 are the zeors of given polynomial .
so,
putting x = 1 in the expression , we get
(1)³ + 10(1)² +a(1) + b = 0
or, 1 + 10 + a + b = 0
or, a + b = -11 --------(1)
again putting x =2
(2)³ +10(2)² +a(2) + b =0
or, 8 + 40 + 2a + b = 0
or, 2a + b = -48 ----------(2)
solving equations (1) and (2)
a = -37 & b = 26
Thanks.
Here is the answer.
Polynomial , x³ +10x² + ax + b is exactly divisible by ( x -1) and (x -2)
it means x = 1 and 2 are the zeors of given polynomial .
so,
putting x = 1 in the expression , we get
(1)³ + 10(1)² +a(1) + b = 0
or, 1 + 10 + a + b = 0
or, a + b = -11 --------(1)
again putting x =2
(2)³ +10(2)² +a(2) + b =0
or, 8 + 40 + 2a + b = 0
or, 2a + b = -48 ----------(2)
solving equations (1) and (2)
a = -37 & b = 26
Thanks.
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