Question

Find the value of a and b so that x3 - ax2 - 13x + b has x-1 and x-3 as factors

Answer 1

Step-by-step explanation:

$p(x) = {x}^{3} - a {x}^{2} - 13x + b$

$p(1) = 0$

${1}^{3} - a \times 1 - 13 \times 1 + b = 0$

$1 - a - 13 + b = 0$

$- a + b = 12 \: \: \: \: \: ....(i)$

$p(3) = 0$

${3}^{3} - a \times {3}^{2} - 13 \times 3 + b = 0$

$27 - 9a - 39 + b = 0$

$- 9a + b = 12 \: \: \: \: \: .......(ii)$Solving eq.(i) and (ii), we get

a =0, b = 12

Answer 2

Answer:

07.07.2021

Step-by-step explanation:

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