Question

find the value of a and b such that.(√3+√2)/(√3-√2)=a+b√6​

Answer 1

Answer:

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Answer 2

$\tt\huge{\blue{Answer:-}}$

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$= \frac{( \sqrt{3})^{2} + 2 \times \sqrt{3} \times \sqrt{2} + (\sqrt{2} ) ^{2} }{( \sqrt{3})^{2} - ( \sqrt{2})^{2} }$

$= \frac{3 + 2 \sqrt{6} + 2 }{3 - 2}$

$= 5 + 2 \sqrt{6}$

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