Find the value of a and b such that px is divisible by x- 1 and X+3
px=x^3-ax^ 2-13 X+ b
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Step-by-step explanation:
p(x)=x³-ax²-13x+b
x-1 is a factor
p(1)=0
p(1)=1³-a(1)²-13(1)+b=0
p(1)=1-a-13+b=0
b-a=12_____(1)
x+3 is a factor
p(-3)=0
p(-3)=(-3)³-a(-3)²-13(-3)+b=0
p(-3)= -27-9a+39+b=0
b-9a= -12_____(2)
(1)-(2)=>8a=24 a=3
b-a=12
b=12+3=15
hope it helps
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