Question

FIND THE VALUE OF A AND B SUCH THAT x=1, x=-2 ARE THE SOLUTION OF THE QUADRATIC EQUATION X2+AX+B=0​

Answer 1

Answer:

Please find the attachment

Answer 2

Answer:

a= 3, b= -2

Step-by-step explanation:

if x= 1

then, x²+ax+b= 0

(1)²+a(1) + b= 0

1+a+b=0

a+b= -1 {equation 1}

if x= -2

then, x²+ax+b=0

(-2)²+a(-2)+b=0

4-2a+b=0

-2a+b= -4 {equation 2}

by subtracting equation 1 from equation 2

a+b-(-2a+b) = -1-(-4)

a+b+2a-b= 3

3a=3

a=3/3

a= 1

a+b= -1

1+b= -1

b= -1-1

b= -2