Question

find the value of 'A' and 'B'
$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } = a \: + b \sqrt{2}$
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Answer 1

Answer:

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Step-by-step explanation:

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } = a + b \sqrt{2} \\ \frac{11 + 6 \sqrt{2} }{7} = a + b \sqrt{2} \\ \frac{11}{7} + \frac{6 \sqrt{2} }{7} = a + b \sqrt{2} \\ so \\ a = \frac{11}{7} \\ b \sqrt{2} = \frac{6 \sqrt{2} }{7} \\ b = \frac{6}{7} \\ ansssssss$