Question

Find the value of A and B when X=10
A= 5x^2 divided by 2
B= 2x^2(x-5) divided by 10x

Answer 1

Step-by-step explanation:

Simplifying

2x + -10 = 10 + -3x

Reorder the terms:

-10 + 2x = 10 + -3x

Solving

-10 + 2x = 10 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.

-10 + 2x + 3x = 10 + -3x + 3x

Combine like terms: 2x + 3x = 5x

-10 + 5x = 10 + -3x + 3x

Combine like terms: -3x + 3x = 0

-10 + 5x = 10 + 0

-10 + 5x = 10

Add '10' to each side of the equation.

-10 + 10 + 5x = 10 + 10

Combine like terms: -10 + 10 = 0

0 + 5x = 10 + 10

5x = 10 + 10

Combine like terms: 10 + 10 = 20

5x = 20

Divide each side by '5'.

x = 4

Simplifying

x = 4

Answer 2

Answer:

A = 250

B = 10

Step-by-step explanation:

Data:

• x = 10

Solution 1:

$\implies$ $\sf{A = {\Large\frac{5x^2}{2}} }$

$\implies$ $\sf{{\Large\frac{5(10)^2}{2}} }$

$\implies$ $\sf{{\Large\frac{5×\bcancel{100}}{\bcancel{2}}} }$

$\implies$ $\sf{5×50 }$

$\therefore$ A = $\boxed{\sf{250 }}$

Solution 2:

$\implies$ B = $\sf{{\Large\frac{2x^2(x-5)}{10x}} }$

$\implies$ $\sf{{\Large\frac{2(10)^2(10 - 5)}{10(10)}} }$

$\implies$ $\sf{{\Large\frac{2×\bcancel{100}(5)}{\bcancel{100}}} }$

$\implies$ $\sf{2 × 5 }$

$\therefore$ B = $\boxed{\sf{ 10 }}$

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