Find the value of a + b -2c when a=3, b=2 and c= -1
Answers
Answered by
0
Step-by-step explanation:
We know that
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
As a+b+c=0, so, a
3
+b
3
+c
3
−3abc=(0)(a
2
+b
2
+c
2
−ab−bc−ca)=0
Hence, a
3
+b
3
+c
3
=3abc.
Answered by
2
So 7 is solution
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