find the value of √A-√B=30°and √B-√C=180°
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So, let’s get started-
In the question, angle A= 105°,
Then, angle B= 30°
So, angle C= 45° (obviously)
And, AC= 8 unit (as you have not provided any specific unit)
So, applying the so called, “Sine Theorem” over here-
sin B/AC = sin C/AB
So, sin 30°/8 = sin 45°/AB
Let’s get this quick-
Putting the value of sin 30° and sin 45°,
AB= 8*{(2)^(1/2)} unit
So, AB= 8*1.414 unit
Thus, we arrived at our final result-
AB= 11.312 unit (approximately)
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