Math, asked by goudgrc, 6 months ago

Find the value of (a-b)(a + b)+(b
-c)(b+c)+(c-a)(c +a) *​

Answers

Answered by bhsrni
10

Answer:

Step-by-step explanation:

(a-b)(a+b) + (b+c)(b-c) + (c-a)(c+a)     { (a+b) (a-b) }

a^{2} - b^{2} + b^{2} -c^{2} + c^{2} - a^{2}

= 0

Hope I was able to help!

Answered by kshitija200639
6

Step-by-step explanation:

(a-b) (a+b) = a²-b²

(a²-b²) + (b²-c²) + (c²-a²)

a² - b² + b² - c² + c² - a²

0 ans

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