Math, asked by usmansonu5252, 1 year ago

Find the value of a, b, & c such that the numbers a, 7, b, 23 and c are in A.P.

Answers

Answered by sanjh9942

7+23/2=b
30/2=b
b= 15
common difference = 8
7-8= a
a= -1
c= 23+8= 31

so value of a, b , c is -1 , 15 and 31 respectively..

hope it helpss!!!!

Pratiksh: can you please say the formula to be used here

Pratiksh: please

sanjh9942: there is no particular formula only the one is add the nos. nad divide them by 2 only

brunomars: the difference is same between two consecutive terms in ap

brunomars: difference=term 2-term1

Answered by brunomars

Answer:

Step-by-step explanation:

This sequence is in ap so , the difference must be equal,

7-a=23-b=c-23=b-7

7-a=b-7

a+b=14

23-b=b-7

2b=30

b=15

a+b=14

a+15=14

a=-1

, Now

c-23=b-7

c = b+16

c= 15+16

c= 31

I hope u loved it

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