Question

find the value of a ,b and c from the given equadratic eguation x square +8x+15=0​

Answer 1

For ax2+bx+c=0, the values of x which are the solutions to the equation are given by:

x=−b±√b2−(4ac)2⋅a

Substituting:

1 for a

8 for b

15 for c gives:

x=−8±√82−(4⋅1⋅15)2⋅1

x=−8±√64−602

x=−8−√42 and x=−8+√42

x=−8−22 and x=−8+22

x=−102

Answer 2

Answer:

(x²) +(8x) +(15) is answer

Step-by-step explanation:

x²+8x+15=(x²)+(8x)+(15)