. Find the value of a, b and c in linear equation x-y/5 -10 = 0
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Answer:
Given equation:
x−y/5−10=0
Rearranging the equation
1x + (-1/5)y + (-10) = 0
If we compare the equation with ax+by+c=0
Then will get
⇒a=1,b=−1/5,c=−10
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