Question

Find the value of a,b, and c in the following quadratic equations
Quadratic equation a b c
1.x² - 4x -5 = 0
2.2x² + x -6 =0
3.x²-3x = -1
4.x²-6x= -2x +7
5.-2x= -3x² +8
pls show me the solution

Answer 1

Answer:

1.Let's solve your equation step-by-step.

x2−4x−5=0

Step 1: Factor left side of equation.

(x+1)(x−5)=0

Step 2: Set factors equal to 0.

x+1=0 or x−5=0

x=−1 or x=5

Answer:

x=−1 or x=5

2.Let's solve your equation step-by-step.

2x2+x−6=0

Step 1: Factor left side of equation.

(2x−3)(x+2)=0

Step 2: Set factors equal to 0.

2x−3=0 or x+2=0

x=3/2 or x=−2

Answer:

x=3/2 or x=−2

3.Let's solve your equation step-by-step.

x2−3x=−1

Step 1: Subtract -1 from both sides.

x2−3x−(−1)=−1−(−1)

x2−3x+1=0

For this equation: a=1, b=-3, c=1

1x2+−3x+1=0

Step 2: Use quadratic formula with a=1, b=-3, c=1.

x=−b±√b2−4ac/2a

x=−(−3)±√(−3)2−4(1)(1)/2(1)

x=3±√5/2

x=3/2+1/2√5 or x=3/2+−1/2√5

Answer:

x=3/2+1/2√5 or x=3/2+−1/2√5

4.Let's solve your equation step-by-step.

x2−6x=−2x+7

Step 1: Subtract -2x+7 from both sides.

x2−6x−(−2x+7)=−2x+7−(−2x+7)

x2−4x−7=0

For this equation: a=1, b=-4, c=-7

1x2+−4x+−7=0

Step 2: Use quadratic formula with a=1, b=-4, c=-7.

x=−b±√b2−4ac/2a

x=−(−4)±√(−4)2−4(1)(−7)/2(1)

x=4±√44/2

x=2+√11 or x=2−√11

Answer:

x=2+√11 or x=2−√11

5.Let's solve your equation step-by-step.

−2x=−3x2+8

Step 1: Subtract -3x^2+8 from both sides.

−2x−(−3x2+8)=−3x2+8−(−3x2+8)

3x2−2x−8=0

Step 2: Factor left side of equation.

(3x+4)(x−2)=0

Step 3: Set factors equal to 0.

3x+4=0 or x−2=0

x=−4/3 or x=2

Answer:

x=−4/3 or x=2