Question

find the value of a^b*b^c* c^d * d^a when a= -1, b= -2, c= -3, d= -4

Answer 1

=a^b*b^c*c^d*d^a
=(-1)^(-2)*(-2)^(-3)*(-3)^(-4)*(-4)^(-1)
=1/{(-1)^2}*1/{(-2)^3}*1/{(-3)^4}1/{(-4)^1}
=1/1*1/-8*1/81*1/(-4)
=1/2592

Answer 2

a^b. b^c. c^d .d^a.

given
a = -1
b = -2
c = -3
d = -4

now,
put the all values of a, b, c, and d in above ,

( -1)^(-2).(-2)^(-3).(-3)^(-4)/(-4)^(-1)

={1/(-1)}^2.{1/(-2}^3 {-1/3}^4.{1/(-4)}^1

=(-1)^2 (-1/2)^3(-1/3)^4.(-1/4)^1

=1 × (-1/8) ×1/81× (-1/4)

=1/32×81

=1/2592