Question

Find the value of a+b+c​

Answer 1

Answer:

squaring both the sides of the given eq. we get

$36 + 16 \sqrt{5 } = {a}^{2} + {b}^{2} c$

By comparing

a = 6

b = 4

and c =

$\sqrt{5}$

so a+b+c =

$6 + 4 + \sqrt{5}$

$= 10 + \sqrt{5}$

Hope it helps...

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Answer 2

6+4√5

a+b+c= 6+4+5= 15

I hope it is correct answer follow me Mark as brainlist answer