Question

Find the value of A+B+C+D in the below given figure ​

Answer 1

Step-by-step explanation:

D=180-80

=100

B=180-100

=80

C=180-70

=110

(as linear pair)

We know sum of all angles of a quadrilateral=360°

80+70+100+(angle opposite to a)=360°

(angle opposite to a )= 360°-250°=110°

a=180°-110°

a=70°

a+b+c+d=?

100+80+110+70

=360°

Sum of all exterior angles =360°

Answer 2

Step-by-step explanation:

Given:l m and p ll q.

To find: The measure of a.b.c.and d.

Answer

a=55

${55}^{0} (vertically \: opposite \: angles \: \\ are \: equal \: \\ a + d = {180}^{0} \: (co - interior \: angles \: \\ supplementary \\ {55}^{0} + d = {180}^{0} \\ d = {125}^{0} \\ c + d = {180}^{0} (co - interior \: angles \\ supplementary \\ c + {125}^{0} = {180}^{0} \\ c = {180}^{0} \\ c = {55}^{0}b + {55}^{0} = {180}^{0}$

$b + c = {180}^{0} (co - interior \: angle \\ are \: supplementary). \\ b + {55}^{0} = {180}^{0} \\ b = {180}^{0} - {55}^{0} \\ b = {125}^{0}$

Hope it helps