Math, asked by pranavhire05, 6 hours ago

Find The Value Of A,B,C For The Quatatic Equation 2y=10-y² By Comparing With Ax²+bx+C=0

Answers

Answered by bulbulamrita17

0

Step-by-step explanation:

$2y = 10 - y { }^{2} \\ = y {2} + 2y - 10 \\ a = 1 \\ b = 2 \\ c = - 10$

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