Find the value of a + b + c, if 900 =(abc)
Answers
Answered by
0
minimum value of a + b + c = 3(30)⅓
but minimum integral value of a + b + c = 10
question is -> find the minimum value of a + b + c , if 900 = (abc)² , where a , b , c ∈ R+
using application,
arithmetic mean, AM ≥ geometric mean, GM
⇒arithrmetic mean of a, b and c = (a + b + c)/3
geometric mean of a , b and c = (abc)⅓
now, (a + b + c)/3 ≥ (abc)⅓
[ given, 900 = (abc)² ⇒ 30 = (abc)
⇒(a + b + c)/3 ≥ (30)⅓
⇒(a + b + c) ≥ 3(30)⅓
so, the minimum value of a + b + c = 3(30)⅓
if you want minimum integral value of a + b + c , then a + b + c = 10
also read similar questions: Is 900 a perfect square? If so, find the number whose square is 900.
https://brainly.in/question/8100827
Estimate 93 x 19.
A 1800 - B 927 - C 1710 - D 900
https://brainly.in/question/5189613
Similar questions
Physics,
6 months ago
Computer Science,
6 months ago
Chemistry,
1 year ago
India Languages,
1 year ago