Math, asked by raosanta429, 10 months ago

Find the value of a + b +c, if 900 =(abc)²​

Answers

Answered by manetho
16

Step-by-step explanation:

Given: (abc)^2= 900

⇒ abc= 30

⇒  now we have factors of thirty as 1,2,3,5,6,10,15

so we can take any three values from the factors of 30 such that their product is 30 and find a+b+c

suppose we a= 1 , b= 5 and c= 6 then abc= 30

and = a+b+c= 1+5+6= 11

similarly, many combination can be made.

Answered by jitendra420156
3

Therefore a+b+c=10 or 14 or 12

Step-by-step explanation:

Given,

(abc)²=900

abc =±30

30= 1×5×2×3

If a=5,b=2 and c=3     Again if a=1,b=10 and c=3

Then a+b+c                   Then a+b+c

       =5+2+3                           =1+10+3

       =10                                  =14

If a=1,b=5 and c=6

Then a+b+c

       =1+5+6

       =12

Therefore a+b+c=10 or 14 or 12

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