Question

find the value of A,B,C in AB×5=CAB
please frist read my question properly then answer with full explanation​

Answer 1

Given:

PS ⊥ RQ

QT ⊥ PR

RQ = 6, PS = 6 and PR = 12

With base PR and height QT, A(△PQR)=12×PR×QT

With base QR and height PS, A(△PQR)=12×QR×PS

∴A(△PQR)A(△PQR)=12×PR×QT12×QR×PS⇒1=PR×QTQR×PS⇒PR×QT=QR×PS

⇒QT=QR×PSPR=6×612=3

Hence, the measure of side QT is 3 units.