Question

find the value of a, b,c of the equation 20v² +5v²+5v+1​

Answer 1

Answer:

As the two matrices are equal, their corresponding elements are also equal.

Comparing the corresponding elements, we get:

a−b=−1 ....(1)

2a−b=0 ...(2)

2a+c=5 ...(3)

3c+d=13 ..(4)

From (2), we have

b=2a

Then , from (1), we have:

a−2a=−1

⇒a=1

⇒b=2

Now, from (3), we have:

2×1+c=5

⇒c=3

From (4), we have:

3×3+d=13

⇒9+d=13⇒d=4

∴a=1,b=2,c=3,andd=4