Question

find the value of a :b if 2/3-3/b=2(3/a-2/b) ​

Answer 1

Answer:

If (a^2 + b^2)^3 = (a^3 + b^3)^2, where a is not = 0, then what is (a/b) + (b/a)?

(a^2 + b^2)^3 = (a^3 + b^3)^2

a^6 +3a^4*b^2 + 3a^2*b^4 + b^6 = a^6 + 2a^3*b^3 + b^6, or

3a^4*b^2 + 3a^2*b^4 = 2a^3*b^3, or

3a^2*b^2(a^2+b^2) = 2a^3*b^3, or

(a^2+b^2)/ab =2/3, or

(a/b) + (b/a) = 2/3. Answ

Answer 2

Answer:

the answer will be 2/3 ..