find the value of a+b if 3+√7÷3_√7=a+b√7
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(3+√7)÷(3+√7)
Rationalising
[(3+√7)(3+√7)]/(3-√7)×(3+√7)
=[(3+√7)^2]/(3)^2-(√7)^2
=16+6√7/9-7
=16+6√7/2
seperate denominators
16/2+6√7/2
=8+3√7
8+3√7=a+b√7
a=8 and b=3
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